Calculate the temperature of 4.0 moles gas occupying 5 dm at 3.32 bar.
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n=4 ,p=3.32 and v=5dm
so,
pv=nrt (ideal gas equation)
t=pv÷rn
t=3.32×5÷8.31×4
t=8°C
so,
pv=nrt (ideal gas equation)
t=pv÷rn
t=3.32×5÷8.31×4
t=8°C
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