Question

calculate the temperature of a furnace, when a 400g of a copper ball, taken out from it , melts only 400g of ice to form water at 0℃ .Taken S.H.C. of copper =0.4J/g ℃ and S.L.H. of ice =336J/g.​

Answer 1

Answer:

Let temp. of furnace i.e. of copper ball = T°C

∴ Heat lost by copper ball = Heat gained by ice to melt to 0°C water

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