Question

calculate the temperature of hot copper sphere having mass 200g when drop in hot water and mass 100g when drop in cold water at 20°C . The temperature of resultant mixture is 60°C​

Answer 1

Explanation:

assuming specific heat capacity of copper to be 385 j/g℃ from std

& for water to be 4.2 kj/kg℃

heat rejected by copper = heat absorbed

by water

0.2*385*(T1-60) = 0.1*4200*(60-20)

(T1-60) = 218.18

T1 = 218.18 +60 = 278.18 ℃