Question

Calculate the the work done by air on expanding from 50 litres to 150 litres at a constant pressure of 2 into 10 to the power 5 Newton per metre square

Answer 1

Work done = 20 KJ

Explanation:

There is a difference in work done formulas in electrical and thermodynamics. In thermodynamics work done is:

W = P∆V

Where, W is work done by/on the gas, and ∆V is change in volume.

P = 2 × 105 Nm^-2

Change in volume = 150 – 50 = 100 liter = 0.1 m^3

So,

W = (2 × 10^5) (0.1)

W = 20 kJ

Answer 2

Work done=20 KJ

Explanation:

$V_1=50 L$

$V_2=150 L$

P=$2\times 10^5 N/m^2$

dV=$V_2-V_1=150-50=100 L=\frac{100}{1000}m^3=0.1 m^3$

Using $1m^3=1000 L$

We know that

Work done=$PdV$

Work done=$2\times 10^5\times 0.1$ J

Work done=$2\times 10^4$J

Work done=$2\times 10^4 J$

Work done=$\frac{2\times 10^4}{1000}=20 KJ$

Using 1000 J=1 KJ

Work done=20 KJ

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