Question

calculate the the work done for lifting 500kg of through vertical of 10m

Answer 1

hi there,
W=Fs
F=ma=500*10(g=10,a=-10)
=-5000
work =5000*10=-50000 joule
i hope this helps u nd pls smash the thanks button 

Answer 2

we know that work done = f * s 
we don't know the force here  
∴ F = ma 
      = 500 * a 
here a = g and the a is " negative " 
⇒ a = - 10 
F = ma 
   = 500 * - 10 
   = - 5000 
∴ work done = f * s 
                     = - 5000 * 10 
                     = - 50000 
∴ the work done = 50000 in upwards direction or even - 50000 
note : I've used the word upward direction to reply the negative symbol