Calculate the thickness of the patients skin if 40% of the incident Xrays were absorbed by his flesh. Let the absorption coefficient be 2 units
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Hii Dear,
◆ Answer -
Thickness of skin = 2.554 mm
◆ Explaination -
Let I0 be the initial intensity of the radiation and I be radiation afterwards.
I/I0 = (100-40)/100
I/I0 = 0.6
Thickness of the patient's skin will be given by -
t = ln(I0/I) / μ
t = ln(1/0.6) / 2
t = -ln(0.6) / 2
t = 0.5108 / 2
t = 0.2554 cm
t = 2.554 mm
Therefore, thickness of the skin will be 2.554 mm.
Thanks dear.
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