Question

calculate the time period of a simple pendulum of length 1.12 m, when acceleration due to gravity is 9.8m s^-2.
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Answer 1

Explanation:

l=1.12m; g=9.8ms

−2

; T=?

T=2π

g

l

=

7

2×22

9.8

1.12

=

7

44

0.114

=

7

44

×0.338=2.12s

Answer 2

Answer:

2.12 s

Explanation:

Time period,T = 2π√(l/g)

T= 2 x 3.14 x √ (1.12/9.8) = 2.12 s