Physics, asked by rajshrigavhane9, 1 year ago

calculate the total cost of running the following electrical devices in the month of september, if the rate of 1 unit of electricity is ₹ 6.00. (1) electric heater of 1000W FOR 5 hours daily. (2) electric refrigerator of 400 W for 10 hours daily

Answers

Answered by shubhamjoshi033
436

The total cost of running these equipment in september will be Rs 1620

Explanation:

One unit is equal to 1 kilowatt hour

1) capacity of electric heater = 1000w = 1 kilowatt

Time used = 5 hours

total kilowatt hour = 1 x 5 = 5Kwh = 5 units

cost of 1 unit = 6 rs

=> cost of 5 units = 6 x 5 = 30 Rs/ day

2) capacity of electric refrigerator = 400 w = 0.4 kilowatt

Time used = 10 hours

total kilowatt hour = 0.4 x 10  = 4 Kwh = 4 units

cost of 1 unit = 6 rs

=> cost of 4 units = 6 x 4 = 24 Rs/day

Hence total cost per day = 30 + 24 = 54 Rs/day

Total cost in September = 30 days x 54 Rs/day = 1620 Rs

Hence the total cost of running these equipment in september will be Rs 1620



shahmanav408: I'm sorry for 1 rating ...It was by mistake....5 stars
Answered by vishalpatil12345
188

Here is your answer I hope it helps you



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