Question

calculate the total no. of electrons flowing through a circuit in 20 mine and 40s, if a current of 40micrometre flows through the circuit

Answer 1

Explanation:

Total charge that flows in 2s is given by 

q=It=5×2=10C

Now, charge on one electron is given by e=1.6×10−19C

N= number of electrons

q=Ne

⟹N=eq

⟹N=1.6×10−1910

⟹N=6.25×1019