Question

Calculate the total number of electrons present in 1.6 g of CH4. ??

Answer 1

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1 mole of methane weighs 16.04 g. 1.6 g of methane, therefore is roughly 0.1 mole. A mole of any substance contains 6.023 X 10^23 molecules. So, 0.1 g of methane contains 6.008 x 10^22 molecules of methane. A methane molecule contains one carbon atom and four hydrogen atoms. Each carbon atom has 6 electrons and each hydrogen atom has one electron adding to a total of 10 electrons in the methane molecule. Thus, 6.008 X 10^22 molecules of methane would contain 6.008 x 10^23 electrons, apart from other matter such as protons and neutrons, of course.

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Answer 2

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$\implies$ Given,

$\implies$ Methane (Ch4)

$\implies$ Molecular mass of CH4 = 12+4×1 = 16 gram/mol


$\implies$ Moles of CH4 = 1.6/16

$\implies$ =0.1 mol.


$\implies$No. of electron in 1 molecule of CH4 = 6+4

$\implies$= 10 electrons

$\implies$Total no. of electrons = 0.1 × 6.022×10^23 × 10

$\implies$= 6.022×10^23 electrons.