Question

Calculate the total number of electrons present in 32 gram of methane

Answer 1

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✔ 1 atom of CH4 contain 10 e^-

No. of moles in CH4 = 32 /10 =2 mol

No. of atom in 2 mol =2×(6.022×10^23 )

No. of electrons = 10×2×(6.022×10^23)

= 12.044 × 10^24 (ans)

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Answer 2

Concept:

The number of particles found in one mole of any substance is referred to as Avogadro's number, also known as Avogadro's constant.

Given:

The mass of methane = 32 g

Find:

Calculate the total number of electrons present in 32 grams of methane.

Solution:

We know that one molecule of methane has 10 electrons.

1 molecule of methane has 6.022 x 10²³ molecules.

The molar mass of methane = 12 g/mol + (4 x 1 g/mol)

= 12 + 4

= 16 g/mol

Therefore, 1 g of methane = 6.022 x 10²³ molecules

So, 32 g of methane = (6.022 x 10²³ molecules x 32 g) / 16 g/mol

10 electrons in 1 molecule of methane =  10electrons x (6.022 x 10²³ molecules x 32 g) / 16 g/mol

= 120.44 x 10²³ electrons

Hence, the total number of electrons present in 32 grams of methane is 120.44 x 10²³ electrons.

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