Question

calculate the total number of oxygen atoms present in 1.80 g of glucose............need the solution plz

Answer 1

Firstly we have to calculate the number of moles by the formula given weight divided by gm.molecular weight then multiply 6×no . of moles × avogadro's no.

Answer 2

Answer: $0.36\times 10^{23}$

Explanation: To calculate the number of moles, we use the equation:

$\text{Number of Moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of glucose $(C_6H_{12}O_6)$ = 180 g/mol

Given mass of glucose = 1.80 g

Putting the values in above equation, we get:  

$\text{Number of Moles}=\frac{1.80}{180g/mol}=0.01 moles$

According to mole concept:

1 mole of  glucose $(C_6H_{12}O_6)$ contains $6\times 6.022\times 10^{23}=36.14\times 10^{23}$ atoms of  oxygen.

0.01 mole of  glucose $(C_6H_{12}O_6)$ contains=$\frac{36.14\times 10^{23}}{1}\times 0.01=0.36\times 10^{23}$ atoms of oxygen