Question

calculate the total number of protons present in 9 gram of water ​

Answer 1

Answer:

5 mole

Explanation:

given mass = 9g

molecular mass of water = 2(1)+16=18g

proton mass in water= 2(1)+8=10g

mole=     given mass    =  9   = 0.5 mole

          molecular mass      18

no. of proton = mole * proton mass

                      =0.5 * 10

                      = 5 mole

Answer 2

Answer:

The total number of protons present in 9 grams of water ​is 3.011×10²⁴.

Explanation:

The total number of protons present in water is calculated as,

$N=n\times N_a\times x$     (1)

Where,

N=total number of protons present in water

n=number of moles of water

$N_a$=Avagadro number=6.022×10²³

x=number of protons in one molecule of water

The molecular formula of water is H₂O. So, the number of protons in water is;

$x=2\times 1+8=10$     (2)

The number of moles of water in the given sample is,

$n=\frac{9}{18}=0.5$        (3)   (The molecular weight of water is 18g)

By putting all the relevant entities in equation (1) we get;

$N=0.5\times 6.022\times 10^2^3\times 10$

$N=3.011\times 10^2^4$

The total number of protons present in 9 grams of water ​is 3.011×10²⁴.

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