Physics, asked by akshatgoyal1792004, 10 months ago

Calculate the total resistance between point A and B as shown in the figure. G stands for galvanometer whose resistance is 110 ohm. It was noticed that the galvanometer didn't show any deflection.​

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Answers

Answered by ajhabinodjha
6

Answer:

Explanation:

effective resistance between A and B:

Resistance along AFE:  4 ohms.

it is in parallel with 4 ohms along AE.  Hence, effective resistance of these two:

       = 4 * 4 /(4+4) = 2 ohms

resistance along AED: 2 ohms + 2 ohms = 4 ohms.

This is in parallel with the resistance along AD : 4 ohms.

Hence the effective resistance :  2 ohms .

This is in series with resistance 2 ohms along CD.  HEnce, total resistance along ADC is 4 ohms.

This is parallel with the 4 ohms resistance along AC.  Effective resistance then is 2 ohms.  This is in series with 2 ohms along BC.

Hence the along ACB the resistance is 4 ohms.

Between A and B there are two  4 ohms resistances in parallel.

Hence, effective resistance between A and B = 2 ohms.

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effective resistance between A and D:

Total resistance along ABC = 6 ohms.

Between A and C we have  4 ohms and 6 ohms in parallel.

equivalent Resistance between A & C along AC:   6*4/(6+4) = 2.4 ohms

Add this to the resistance 2 ohms between C and D.  Hence, Along ACD the resistance is 4.4 ohms.

similarly, on the other side, Equivalent resistance along AED will be 4.4 ohms, from symmetry.

Now, 4 ohms between A and D, 4.4 ohms along AED,  and  4.4 ohms along ACD are all in parallel.

equivalent resistance along AD:   R  (say).

  1/ R = 1/4 + 1/4.4 + 1/4.4 =  (1.1 +1+1)/4.4 = 3.1/4.4

     R  =  4.4 / 3.1 ohms = 1.42  ohms.

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