Question

calculate the total sigma and pi bonds 2 amino cyclopent 3 ene 1 carboxylic acid​

Answer 1

Answer:

compound/1R_2S_-2-Aminocyclopent-3-ene-1-carboxylic-acid

(1R,2S)-2-Aminocyclopent-3-ene-1-carboxylic acid ... - PubChem

Explanation:

hope it helps you

Answer 2

Some general information -

=> Sigma (σ) bonds and pi (π) bonds form the basis of covalent bonding.

=> Each single covalent bond contains 1 sigma bond.

=> Each double covalent bond contains 1 sigma bond and 1 pi bond.

=> Each triple covalent bond contains 1 sigma bond and 2 pi bonds.

Some definitions to be clear with -

1) Root word -

=> The root word indicates the number of carbon atoms present in the longest continuous Carbon chain in the molecule.

=> It may be "meth" , "eth" , "prop" , "but" , "pent" etc if the number of carbon atoms are 1,2,3,4 respectively.

2) Prefix -

=> The prefix of the IUPAC name indicates the substituents present and their respective locants (numbering) .

3) Primary suffix -

=> The primary suffix is placed just after the root word, it gives us the type of Carbon-Carbon bonds present in the longest Carbon chain, whether they are single (C-C) , double (C=C) or triple (C≡C) or one or more of them present in the same molecule.

4) Secondary suffix -

=> The secondary suffix is present just after the primary suffix and gives us the principal functional group present in the molecule and its locant (if any) .

=> The numbering always gives the principal functional group the lowest possible locant.

Drawing the entire structure -

=> First, draw the entire, branched structural formula showing all the bonds.

=> Given IUPAC name is 2-Aminocyclopent-3-ene-1-carboxylic acid

=> Follow the following steps to draw the structure -

• First, look at the root word, here it is "cyclopent" indicating that the longest continuous carbon chain consists of 5 Carbon atoms arranged in a pentagonal structure in a closed chain.

• Now, look for the secondary suffix which gives us the principal functional group, here, it is "1-carboxylic acid" indicating that a             -COOH group is present at locant number 1 .

• Now, look for the primary suffix, here, it is "3-ene" indicating that there is a double C=C bond present at locant number 3.

• Now, look for the prefix which gives us the substituent/s , here, it is         "2-Amino" indicating that an amino (-NH2) group is present attached to the Carbon atom numbered with the locant 2.

=> Satisfy the valency of Carbon (4) using Hydrogen atoms, show them with individual single bonds.

=> Finally, complete the structure, it is attached as an image below.

Finding the no. of σ and π bonds -

=> To do this proceed as under -

[1] Find the number of single bonds, double bonds and triple bonds present from the complete structure drawn.

• No. of single bonds - 16
• No. of double bonds - 2
• No. of triple bonds - 0

[Let the number of single, double and triple bonds present respectively be x, y & z] .

• x = 16
• y = 2
• z = 0

[2] The number of sigma (σ) bonds is given by (x + y + z)

     The number of pi (π) bonds is given by (y + 2 × z)

=> σ bonds = 16 + 2 + 0

                   = 18 σ bonds

=> π bonds = 2 + 2 × 0

                   = 2 π bonds

Answer -

=> The molecule contains 18 sigma bonds and 2 pi bonds in it.