calculate the total surface area of the outside of an open box (without a lid) which has a base measuring 1.0 m by 0.8 m and has a height of 0.5 m
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S.A= C. S. A of box + lb
l=1.0
b=0.8
h=0.5
so,
S.A= 2h(l+b) + lb
2*0.5(1.0+0.8) + 1.0*0.8
(1) (1.8) + 0.8
1.8 + 1.8
3.6m^2
I hope so it helps u☺☺
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