Question

calculate the value acceleration due to gravity at a place 3200km above the surface of earth.

Answer 1

Assume-
     h= 3200km = 3200000m = 3.2 x10^6
     R= 6400km = 6400000m = 6.4 x 10^6
     g= 9.8m/s^2
We know that-
           g'= g[R^2/(R+h)^2]
              = 9.8(40.96 x 10^12/92.16 x 10^12)
              = 9.8 x 4/9
              = 4.355m/s^2 ~ 4.4m/s^2

Thus, value of g at a place 3200km above surface of the earth is 4.4m/s^2.

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