Question

calculate the value for one einstein for 6000 angstrom ​

Answer 1

Answer:

Explanation:

:

Frequency `v = (c)/(lamda)` <br> Substituting `c = 3 xx 10^(8) m s^(-1), lamda = 6000 Å= 6000 xx 10^(-10) m`, we get <br> `v = (3 xx 10^(8) ms^(-1))/(6000 xx 10^(-10)m) = 5 xx 10^(4) s^(-1)` <br> (ii) Energy of the photon E = hv <br> Substituting `h = 6.625 xx 10^(-34) J s, v = 5 xx 10^(14) s^(-1)`, we get <br> `E = 6.625 xx 10^(-34) J s xx 5 xx 10^(14) s^(-1) = 3.3125 xx 10^(-19) J`