Question

Calculate the value of 100j in a system based upon cm,kg,and minute as the fundamental unit

Answer 1

Explanation:

[J]=[ML²T-²]

a=1, b=2, c=-2

n1=100. n2=?

M1=1kg. M2=1kg

L1=1m=100cm L2=1cm

T1=1s. T2=1min=60s

since,

n2=n1[M1/M2]^a [L1/L2]^b [T2/T2]^c

n2=100[1/1]¹ [100/1]² [1/60]-²

n2=(100*10000)/3600

n2=10000/36=2500/9

Answer 2

Answer:

3.6 x[J]=[ML²T-²]

Explanation:

[J]=[ML²T-²]

a=1, b=2, c=-2

n1=100. n2=?

M1=1kg. M2=1kg

L1=1m=100cm L2=1cm

T1=1s. T2=1min=60s

Therefore,

n2=n1[M1/M2]^a [L1/L2]^b [T2/T2]^c

n2=100[1/1]¹ [100/1]² [1/60]-²

n2=(100*10000*3600)

n2 = 3.6 x 10^9

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