Question

Calculate the value of a current I in the circuit given below

Answer 1

Answer:

0.1 A

Explanation:

The equivalent resistance =

$\frac{(30 + 30)30}{(30 + 30) + 30}$

$= \frac{1800}{90}$

$= 20$

current I =

$\frac{v}{r}$

$= \frac{2}{20}$

= 0.1

Answer 2

Answer:

0.1 Ampere

Explanation:

Given:

• Voltage (potential difference) = 2 Volts
• 3 resistors of 30 ohms are connected in a triangualr setup as shown in the attachment

To find:

• Value of current in the circuit

Let the resistor between A and B be R₁, Let the resistor between B and C be R₂ and let the resistor between A and C be R₃

Here,

R₁ and R₂ are in series: When any two resistors are in series, Req = R₁+R₂

R₁+R₂=30Ω+30Ω

R₁+R₂=60Ω

Now this whole thing will be in parallel with the R₃

When any two resistors are in parallel, Req = $\frac{R1\times R2}{R1+R2}$

Req = $\frac{60 \times 30}{60+30}$

Req = $\frac{1800}{90}$

Req = 20Ω

Now using ohms law:

V=IR

2=I×20

I=2/20

I = 0.1 Amperes

The value of the current in this question is equal to 0.1 Ampere