Calculate the value of delta x. delta u for
an electron , where
(mass of an electron =9.1x10-31 kg).
Answers
Answer:
answer
Explanation:
ording to Heisenberg’s uncertainty principle, the product of uncertainties in position (Δx) and velocity \(\bigtriangleup v\geq \frac{h}{n\pi }\)
Question says, ‘accurate up to 0.001%’.
This indicates that the uncertainty in velocity is 0.001% of actual value, 300 m.s-1
That is, uncertainty in velocity (Δv) = \(\frac{300\times 0.001}{100}\) = 3 x 10-3 m.s-1
Therefore, the uncertainty in position (Δx) can be calculated as follows:
\(\bigtriangleup x=\frac{h}{4\pi m\bigtriangleup u}\) \(\bigtriangleup x=\frac{6.626\times 10^{-34}\times \times 100}{4\times 3.14\times 9.1\times 10^{-31}\times 0.001\times 300}\) = 1.93 x 10-2m.
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1 Comment
Ankan Chatterjee MAY 28, 2020 AT 7:02 PM
Thanks! I got my doubt clear.
REPLY
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