Calculate the value of E, for given circuit, when value of 2 amp current is either flowing in clockwise or anticlockwise direction
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Given: Two resistors of 6 ohm and 3 ohm, 20 V
To find: The value of E, for given circuit, when value of 2 amp current is either flowing in clockwise or anticlockwise direction.
Solution:
- Now we have given two resistors of 6 ohm and 3 ohm.
- Lets consider the current flowing is in the clockwise direction, then:
- According to Kirchhoff's law, we have:
(6 x 2) + (3 x 2) = E - 20
12 + 6 = E - 20
18 = E - 20
E = 38 V
- Lets consider the current flowing is in the anti - clockwise direction, then:
- According to Kirchhoff's law, we have:
(6 x 2) + (3 x 2) = - ( E - 20 )
12 + 6 = - E + 20
18 = - E + 20
E = - 18 + 20
E = 2 V
Answer:
So the value of E when value of 2 amp current is either flowing in clockwise direction is 38 V and anticlockwise direction is 2 V.
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