Question

calculate the value of force that is applied for 1 second on a 10kg object to increase it's velocity from 5m/s to 10m/s
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Answer 1

Answer:

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Explanation:

Here as the mass 10 kg is considered to be constant, so it depends over the nature of its instantaneous velocity. If it is moving with uniform velocity 10 m/s, then the resultant force must be zero.

Answer 2

$\bold{Given :-}$

$\bold{mass \: = \: 10kg}$

$\bold{time \: = \: 1sec}$

$\bold{initial \: velocity \: (u) = 5m/s}$

$\bold{final \: velocity (v) \: = 10m/s}$

$\bold \red{acceleration \: = \frac{v - u}{t}}$

$\bold{a \: = \: \frac{10 - 5}{1} }$

$\bold{a \: = \: 5m/s²}$

$\bold \red{force \: = \: m \times a}$

$\bold{force \: = \: 10kg \: \times 5m/s²}$

$\bold \green{force \: = 50N.... \: \: \: ans}$