Calculate the value of ‘g’ at a height of 12800 km from the centre of the earth (radius of earth is 6400 km). Draw its interpretation.
Answers
therfore, g=GM/R^2
here, height is given 12800km
(R+H) must use in the above formula
g=GM/(R+H)^2
we have to take distance and radius in meters
therefore, R=6400000
and, H=12800000
g=6.67*10^-11 * 6*10^24/(6400000+12800000)^2
g=40.02*10^13/(19.2*10^6)^2
by solving above equation, we get,
g=1.09m/s^2
I HOPE YOU WILL SATISFIED WITH THIS ANSWER
The value of acceleration due to gravity 'g' at a height of 12800 km from the centre of the Earth is equal to 2.45 ms⁻².
Given:
The height from the centre of the Earth = 12800 km
The radius of the Earth = 6400 km
To Find:
The value of g at a height of 12800 km from the centre of the earth.
Solution:
→ The value of acceleration due to gravity g at a height 'h' above the Earth's surface is given as:
- where g' is the acceleration due to gravity at a height 'h' above the Earth's surface.
- where 'R' is the radius of the Earth.
→ In the given question:
The acceleration due to gravity at the Earth's surface (g) = 9.8 ms⁻²
The radius of the Earth (R) = 6400 km
The height from the centre of the Earth = 12800 km
∴ The height from the surface of the Earth (h) = 12800 - 6400 = 6400 km
Let g' be the acceleration due to gravity at a height 'h' above the Earth's surface.
→ The value of g' comes out to be equal to 2.45 ms⁻².
Therefore the value of acceleration due to gravity 'g' at a height of 12800 km from the centre of the Earth is equal to 2.45 ms⁻².
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