calculate the value of G universal gravitational constant. plzzz send pic of the solution with every steps and solve by your own.... (class 9th) (chapter gravitation)
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g=G Me Mm/r2
g=gravitational force.
Me= mass of Earth.
Me= mass of moon.
R= radius.
g=gravitational force.
Me= mass of Earth.
Me= mass of moon.
R= radius.
Answered by
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The value of G was determined experimentally by Henry Cavendish in 1798 with a instrument called Cavendish balance.
If " GmM/r^2" is the gradational force between the spheres and " GmM /r^2×d" is the torque which produce twist " 0(
" angle in the fibre .
then
GmM/r^2×d directly proportional to theta .
or GmM/r^2 ×d= C theta.
G = gradational constant.
M= mass
R= radius
the accepted value of G = 6.67×10^-11N-M^2)kg^2
.... maybe..... helpful....
plz.... Mark...as.. brain list...
If " GmM/r^2" is the gradational force between the spheres and " GmM /r^2×d" is the torque which produce twist " 0(
" angle in the fibre .
then
GmM/r^2×d directly proportional to theta .
or GmM/r^2 ×d= C theta.
G = gradational constant.
M= mass
R= radius
the accepted value of G = 6.67×10^-11N-M^2)kg^2
.... maybe..... helpful....
plz.... Mark...as.. brain list...
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