calculate the value of tan60 geometrically
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If we consider,any right angled triangle ABC,right angled at B.
AB=Adjacent side=√3 a.
BC=Opposite side= a.
Hypotenuse=AC=2a=∠ACB=60°.
Tan 60°=AB/BC=√3a/a = √3.
HENCE PROVED.
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PLEASE MARK IT AS BRAINLIEST...
AB=Adjacent side=√3 a.
BC=Opposite side= a.
Hypotenuse=AC=2a=∠ACB=60°.
Tan 60°=AB/BC=√3a/a = √3.
HENCE PROVED.
HOPE IT HELPS U...
PLEASE MARK IT AS BRAINLIEST...
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