Question

calculate the value of unknown resistant x in the Circuit​

Answer 1

Answer:

Given,

V=6V

I=0.4A

V=I×R

6=0.4×R

R=15ohm

Therefore,Total resistance in Series Circuit=15ohm

Again,Total resistance in parallel circuit,

$\frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} = \frac{1}{r} \\ = > \frac{1}{12} + \frac{1}{6} + \frac{1}{3} = \frac{1}{r} \\ = > \frac{7}{12} = \frac{1}{r} \\ = > r = \frac{12}{7} ohm$

Therefore,

Total resistance(R) in whole circuit= 15+12/7=117/7ohm

,

Therefore,

Resistance in series=r1+r2+r3.....

R=2+12/7+x

117/7=26/7+×

x=91/7ohm