Question

Calculate the valume in dm3 occupied by 60.0g of ethane s tp

Answer 1

Answer:

22.4dm3

Explanation:

no no that one mole of any gas occupies 22.4 DM cube volume at standard temperature and pressure

Answer 2

The required volume = $44.8 dm^{3}$.

Explanation:

• At STP conditions 1 mole of gas occupies 22.4 litres of volume
• 1 l = 1 $dm^{3}$
• Molecular weight of ethane is 30g
• Given weight = 60g
• No.of moles of ethane = 2
• 2 moles of ethane occupies 44.8 l of volume