If sec thetha + tan thetha= √3, 0< thetha < pi , then thetha is equal to...
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Step-by-step explanation:
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Answer:
thetha = pi/6
Step-by-step explanation:
sec thetha + tan thetha= √3
=> sec thetha = √3 - tan thetha
On squaring both the sides :
sec^2thetha = (√3 - tan thetha)^2 (1)
As we know that :
[ sec^2thetha = 1 + tan^2thetha ]
Now, from equation (1)
=> 1 + tan^2thetha = 3 - 2√3tan thetha + tan^2thetha
=> -2 = -2√3tan thetha
=> tan thetha = 1/√3
=> thetha = 30
=> thetha = pi/6
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