Question

Calculate the vapour pressure at 100°c of a solution containing 15.6 g of water and 1.68 g of sucrose

Answer 1

Vapour pressure of the solution :

P(s) = X(solvent) × P°

Where:

P(s) = vapour pressure of the solution

X = Mole ratio of the solvent.

P° = Vapour pressure of pure solvent.

The vapour pressure of water at 100°C is 658 Torr

Mole ratio of solvent (water) = moles of solvent (water) / total moles

Moles of water :

15.6 / 18 = 0.8667 moles

Moles of sucrose :

1.68 / 343 = 0.004898 moles

Total moles :

0.8667 + 0.004898 = 0.8716 moles

Mole ratio of water = 0.8667 / 0.8716 = 0.9944

Substituting in the formula :

P(s) = 0.9944 × 658.0

= 654.3 Torr

Answer 2

Answer:

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Explanation:

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