Chemistry, asked by drishti1003, 11 months ago

calculate the velocity acquired by an electron moving through a potential difference of 30kV

Answers

Answered by afnan1141

2

maximum kinetic energy aquired by an electron is ev

where v is potential difference between the two terminals

so,

½mv²=ev

to solve where

m=9.1×10—31

charge on an electron=1.6×10—19COULUMB

Explanation:

PUT IN EQUATION AND GET ANSWER

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