Question

Calculate the velocity of a body, released from 40 m height, when it touches the ground. (g = 9.8 m/s²)

Answer 1

HIII....

HERE IS YOUR ANSWER:------

9.8×4.03=39.494

Answer 2

Answer:

Explanation:

We know the equation of motion:

h=(1/2)gt^2,where g is acceleration due to gravity and t is time.Hence,t=4.03s,after substituting the values.v=gt,where v is velocity and t is time.

=>v=9.8*4.03=36.6m/s

Hope you understood