Question

calculate the velocity of efflux of a liquid of density 1.2*10^3 kgm^-3 from a tank in which the pressure of the liquid is 100 Nm^-2.​

Answer 1

Answer:

The velocity of efllux = 0.408 m/s

Explanation:

Given that

$\rho=1200\ \frac{kg}{m^3}$

Pressure of liquid = 100 Pa

We know that velocity of efflux given as follows

$V=\sqrt{2\dfrac{P}{\rho} }$

Now by putting the values in the above equation

$V=\sqrt{2\dfrac{P}{\rho} }$

$V=\sqrt{2\times \dfrac{100}{1200} }$

V=0.408 m/s

So the velocity of efllux = 0.408 m/s