calculate the velocity of electrons Bohr's first orbit of hydrogen atom
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Answer:
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Step-by-step explanation:
1)vn=2. 18×106×nZm/s.
2) thus for Hydrogen v1(H)=2. 18×106×11 m/s.
3) or the velocity of electron present in first Bohr orbit of hydrogen atom=v1(H)=2. 18×106 m/s.
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Answer:
The velocity of an electron in the first Bohr orbit of hydrogen atom is `2.19 xx 10^(6)ms^(-1)`.
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