Question

Calculate the voltage drop across resistance R4 in the circuit. ​

Answer 1

Answer:

963936939(-$$6()-$-)$-6($6)$)

Answer 2

Answer:

Voltage drop is 100V.

Given:

Circuit with R₁ = 36Ω, R₂ = 40Ω, R₃ = 60Ω, R₄ = 50Ω

Voltage = 220V

To find:

Voltage drop across R₄ = 50Ω

Step-by-step explanation:

First find the net resistance of circuit

As, R₂ = 40Ω, R₃ = 60Ω are connected in parallel

$\frac{1}{R_{res} } = \frac{1}{40} + \frac{1}{60} \\R_{res} = \frac{60 * 40}{60 + 40} \\R_{res} = \frac{240}{100}\\ R_{res} = 24$

Rnet =  R₁ + Rres + R₄

Rnet = 36 + 24 + 50

Rnet =  110

Now, calculate current in the circuit.

$V = IR\\220 = 110I\\\frac{220}{110} = I\\I = 2A$

hence, current in the circuit is 2A.

Now, calculate voltage drop across 50Ω resistor.

we know,

$V=IR\\V = (2) (50)\\V = 100$

Therefore voltage drop across 50Ω resistor is 100V.

#SPJ2