Calculate the volume at ntp occupied by 14 gram of nitrogen
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Answered by
1
28 gram N2 occupies 22.4 lt
so 14 gram of N2 will occupy 11.2 lt
so 14 gram of N2 will occupy 11.2 lt
Answered by
4
Given wt = 14 g
molecular wt = 28 g/mol
no of mole = given wt/molecular wt
= 14/28 = 0.5
volume = no of mole × 22.4 L
= 0.5 × 22.4 L
= 11.2 L
molecular wt = 28 g/mol
no of mole = given wt/molecular wt
= 14/28 = 0.5
volume = no of mole × 22.4 L
= 0.5 × 22.4 L
= 11.2 L
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