Question

Calculate the volume (in cm^3) of air expelled from a vessel containing 0.4 litres of it at 250K, when it is heated to 27 degree celcius at the same pressure

Answer 1

Data:

V1 = 400 ml ;

T1 = 250 K

V2 = ?            ;  

T2 = 27 oC = 300 K

V1/T1=V2/T2

or V2 = [T2*V1] / T1

=300 K×400 ml / 250 K

=480 ml

Volume of air expelled from the vessel = 480 - 400 = 80 ml

or 80 cc     ANS

Answer 2

Answer: 80 cc

Explanation:Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$    (At constant pressure and number of moles)

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Given:

$V_1$ = 0.4 L

$T_1$250 K

$V_2$ = ?  

$T_2=27^0C$=27+273=300 K

$\frac{0.4L}{250K}=\frac{V_2}{300K}$

$V_2=0.48K$

Volume of air expelled from the vessel = (0.48-0.4)L =0.08L= $80cc$(1L=1000c)