Math, asked by niahl, 1 year ago

Sin A - 2 Sin cube A upon 2 cos cube A - Cos A is equal to tanA

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Answered by SweetyVargheseReben
6
I think it helps you
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niahl: mention not
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Answered by Anonymous
3
Hola there,

Given=>
 \frac{sin \: a - 2 {sin}^{3}a }{cos \: a - 2{cos}^{3}a } = tan \: a

LHS
=>  \frac{sin \: a \: - 2{sin}^{3}a }{cos \: a \: - 2 {cos}^{3} a}

=>  \frac{sin(1 - 2{sin}^{2} a)}{cos(1 - 2{cos}^{2} a)}

=>  \frac{sin(1 - 2(1 - {cos}^{2} a)}{cos(1 - {cos}^{2} a)}

=>  \frac{sin(1 - {cos}^{2} a)}{cos( 1 - {cos}^{2}a) }

=>  \frac{sin \: a}{cos \: a}

=> tan \: a

=> RHS

So, LHS = RHS

HENCE PROVED.

Hope this helps.....:)

niahl: thnks
Anonymous: wlc
niahl: wlm Q aapne to meri hi help ki he
Anonymous: :-)
niahl: in which class are you
Anonymous: 10th
niahl: i m in also 10th
Anonymous: good
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