Calculate the volume in dm3 occupied by 60.0 g of ethane of STP.
Answers
Answered by
12
Answer:
22.4DM3
Explanation:
that 1 mol of any gas occupied the volume of 22.4 DM3
Answered by
83
Answer:
48.8 dm³
Explanation:
Given -
Molecular formula of ethane = C2H6
Mass of ethane = 60 g
molar mass of ethane = 24g + 6 g → 30 g
Mole of ethane = given mass / Molar mass = 60 / 30 = 2 Mol
Number of mole = V/ 22.4 L
V = 2 × 22.4 ( L) = 44.8 L
Since 1 L = 1 dm³
Therefore volume of ethane = 48.8 dm³
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