Question

Calculate the volume in L occupied by 0.842 mol of nitrogen gas at a pressure of 1.29 atm and a temperature of 312K. Note that R has a value of 0.0821 L atm/mol K. Report answer to 3 sig figs.

Answer 1

Answer:

16.7

Explanation:

by gas equation

we know Pv = nRT

so P( pressure) = 1.29

    n( no. of moles) = 0.842

    R = 0.0821

    T = 312

so by putting the values we get,

1.29* v = 0.842* 0.0821* 312

so v =  (0.842* 0.0821* 312)/1.29

by solving we get,

v = 16.71937860465116

upto 3 significant figure the answer is 16.7

thank you