Question

calculate the volume occupied at STP by 6.022 × 10^23 molecules of carbon dioxide​

Answer 1

Answer:

Answer: The volume occupied will be 22.176 L.

Explanation:

We are given:

Number of molecules = 6.023\times 10^{23}6.023×10

23

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23}6.022×10

23

number of molecules.

At STP:

1 mole of a compound occupies 22.4 L of volume.

which means that 6.022\times 10^{23}6.022×10

23

number of molecules occupy 22.4 L of volume.

Thus, 6.023\times 10^{23}6.023×10

23

number of molecules will occupy \frac{6.022\times 10^{23}}{6.023\times 10^{23}}\times 22.4L=22.176L

6.023×10

23

6.022×10

23

×22.4L=22.176L of volume.

Thus, the volume occupied will be 22.176 L.

Explanation:

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