Question

calculate the volume occupied by 10^22molecules of gas at 300 K and 760 mm pressure

Answer 1

the formula is : PV= nRT
you must be knowing the abbreviation
P_pressure
V_volume
n_no. of moles
R_universal gas constant
T_temperature

now for no. of moles
= no. of molecules * avagadros number
= 10 to power 22 × 6.022× 10 to power 23
=6.022×10 to power 45 moles

now put all the values in the formula

V= nRT/P
V= 6.022×10power45×62.36×300/760s
V=148.23 L

this will be the final answer