Calculate the volume occupied by 2 gram of hydrogen at 27 degree Celsius and 4 atmospheric pressure if at STP it occupies 22.4 litres.
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Moles of hydrogen = 2/2 = 1 mol
Temperature = 27 + 273 = 300K
PV = nRT
V = nRT / P
V = (1 * 0.0821 * 300) / 4
V = 6.15 L
Temperature = 27 + 273 = 300K
PV = nRT
V = nRT / P
V = (1 * 0.0821 * 300) / 4
V = 6.15 L
Answered by
1
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