Question

Calculate the volume occupied by 2 gram of hydrogen at 27 degree Celsius and 4 atmospheric pressure if at STP it occupies 22.4 litres.

Answer 1

Moles of hydrogen = 2/2 = 1 mol
Temperature = 27 + 273 = 300K

PV = nRT
V = nRT / P
V = (1 * 0.0821 * 300) / 4
V = 6.1575 L

Answer 2

Using the ideal gas equation PV=nRT,we can find the volume
Given,
T=27℃=27+273=300K
n=given wt/gram atomic weight
=2/2=1
P=4atm, R=0.0821 L atm K^-1 mol^-1
PV=nRT
(4)V=1(0.0821)(300)
V=6.1575 L

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