Question

Calculate the volume occupied by 2 moles of an ideal gas at2.5x105 Nm-2 pressure

and 300K temperature.(R= 8.314 NmK-1mol-1

)​

Answer 1

Answer:

T = 300k

p= $2.5 \times {10}^5 {nm}^ - 2$

n= 4 moles.

v = $\frac{n \times r \times t}{p}$

= $\frac{4 \times 8.3 \times 300}{ {10}5{?} }$

$\frac{ {10}4{} }{2.5 \times {10}5{} } </em><em>$⇒$4 \times {10} - 2{?}$

= $0.04 {m}3{}$

Explanation:

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