Question

calculate the volume occupied by 28 g nitrogen gas at STP​

Answer 1

Answer:

44.8 litre

Explanation:

Here moles of nitrogen=given mass /molar mass

=28/14

=2 moles

as we know one mole of any gas occupy 22.4 litre at STP

so 2 moles will occupy

=2×22.4

=44.8 litres

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