calculate the volume occupied by 7g of nitrogen gas at 27⁰CAnd 750 mm of Hg pressure (a) 7.8 liter. (b)4.2 liter (c) 6.2 liter (d) 10. 2 liter
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Moles of Nitrogen = Weight / Molar mass
= 7 g / (28 g/mol)
= 0.25 mol
Pressure = 750 mm Hg
= (750/760) atm ………[∵ 1 atm = 760 mm Hg]
= 75/76 atm
From ideal gas equation
V=nRT/P =0.25mol×0.0821atm.L/(molK) *300K/(75/76atm)
=6.2396 liters
The volume occupied by the gas is 6.2396 litres
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Answered by
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Answer:
Moles of Nitrogen = Weight / Molar mass
= 7 g / (28 g/mol)
= 0.25 mol
4G
48
Pressure = 750 mm Hg
= (750/760) atm [ 1 atm = 760 mm =
Hg]
= 75/76 atm
From ideal gas equation
V=nRT/P =0.25molx0.0821atm.L/(molk) *300K/(75/76atm)
=6.2396
The volume occupied by the gas is 6.2396L
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