calculate the volume of 220gm of co2 at STP. Also calculate the number of co2 gas molecules in it.
Answers
Answered by
0
Answer:
CaCO
3
+2HCl⟶CaCl
2
+H
2
CO
3
HCl is limiting reagent so the moles of H
2
CO
3
=10
−1
mol
Now-
H
2
CO
3
⟶H
2
O+CO
2
n mole of H
2
CO
3
will give same amount of mole for CO
2
The no. of mole of CO
2
=10
−1
mole
The volume of CO
2
-
mole=
22.4
Volume
10
−1
=
22.4
volume
Volume=2.24L
Answered by
2
1 mole of co2=44g
220g=5 moles
no° of molecules =6.022×5×10^23 molecules
1 mole=22.4 l
5 mole=112l
ANS :volume=112l
no bn of molecules=6.022×5×10^23
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