Calculate the volume of 2g of CO2 gas at 23degree Celsius and 710 mm pressure
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Answer: Use PV= nrt where pressure is equal to 7 10 / 760 atm, volume we have to calculate temperature is given to be 300 Kelvin, You can take R is equal to 0.0821 and the number of moles is equal to 2 divided by 44 and You will get volume as approximately equal to 1.2 litres.
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Explanation:
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Given
- 2g of CO2 gas.
- Temperature = 23° C
- Pressure = 710 mm
To find
- Volume occupied.
Solution
Now we know that -
→ 760 mm Hg = 1 atm
• Pressure = 710 mm
→ P = 710/760 atm
→ P = 0.934 atm
Now number of moles of CO2 :
We know, molar mass of CO2 = 44 g
→ n = 2 × (1 mol/44g)
→ n = 0.045 moles
We will take R = 0.0821 atmL/mol K
Now temperature :-
We have convert celsius into Kelvin :
→ T = (23 + 273) k
→ T = 296 k
Now using Ideal Gas law :-
→ PV = nRT
→ 0.934 × V = 0.045 × 0.0821 × 296
→ 0.934V = 1.094
→ V = 1.094/0.934
→ V = 1.17 l
Hence volume occupied = 1.17 litres.
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