Question

calculate the volume of 56 gram of nitrogen at 300k amd 1.5 atm pressure
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Answer 1

Answer:

The correct Answer is 24

Answer 2

Answer:

32.84L

Explanation:

let volume be V

given mass of nitrogen =56gm

molar mass of N2=28gm

moles of N2=56/28=2

pressure =1.5atm

temperature=300k

so by ideal gas equation:-

PV=nRT

(R=0.0821 atm m^3/K in case when pressure in atm is given)

1.5 x V= 2 x 0.0821 x 300

V=(2 x 0.0821 x 300)/1.5

V=32.84 Litres